2x(y)dx+(x^2+cos(y))dy=0

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Solution for 2x(y)dx+(x^2+cos(y))dy=0 equation:


Simplifying
2x(y) * dx + (x2 + cos(y)) * dy = 0

Multiply x * y
2xy * dx + (x2 + cos(y)) * dy = 0

Multiply xy * dx
2dx2y + (x2 + cos(y)) * dy = 0

Multiply cos * y
2dx2y + (x2 + cosy) * dy = 0

Reorder the terms:
2dx2y + (cosy + x2) * dy = 0

Reorder the terms for easier multiplication:
2dx2y + dy(cosy + x2) = 0
2dx2y + (cosy * dy + x2 * dy) = 0
2dx2y + (cdosy2 + dx2y) = 0

Reorder the terms:
cdosy2 + 2dx2y + dx2y = 0

Combine like terms: 2dx2y + dx2y = 3dx2y
cdosy2 + 3dx2y = 0

Solving
cdosy2 + 3dx2y = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3dx2y' to each side of the equation.
cdosy2 + 3dx2y + -3dx2y = 0 + -3dx2y

Combine like terms: 3dx2y + -3dx2y = 0
cdosy2 + 0 = 0 + -3dx2y
cdosy2 = 0 + -3dx2y
Remove the zero:
cdosy2 = -3dx2y

Divide each side by 'dosy2'.
c = -3o-1s-1x2y-1

Simplifying
c = -3o-1s-1x2y-1

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